Neutron
bubbles have a radius r equal to 1,3205 fm. This radius is strictly
equal to the Compton wavelength of the neutron.

At
the pole, the linear speed of rotation of bubbles is v =
rω

My
hypothesis is that at the pole, v = c, c = speed of light

Thus,
we obtain: ω = c / r

Then, we know that: ω =
2πν

(ν is the frequency of rotation of bubbles)

So
we obtain: ω
= c / r = 2πν

Then:
2π r = c / ν = λ_{Cbubble}
,

λ_{Cbubble} from is the compton
wavelenght of rotating bubbles

We know that radius r of
bubbles is equal to the Compton wavelength of the neutron:

λ_{Cneutron}
= 1,3205 fm

We
obtain: 2π
λ_{Cneutron} = λ_{Cbulle}

If
the Compton wavelength of rotating bubbles of neutron is 2π times more
high that Compton wavelength of the neutron, we can deduce that its
mass (Mbn) is 2π times more low.

Mbn = Mn/2π

The
same calculus allows to obtaining the mass of the bubbles of proton
(Mbp):

Mbp = Mp/2π