Relativistic mass of rotating bubbles

Neutron bubbles have a radius r equal to 1,3205 fm. This radius is strictly equal to the Compton wavelength of the neutron.

At the pole, the linear speed of rotation of bubbles is v = rω

My hypothesis is that at the pole, v = c, c = speed of light

Thus, we obtain:     ω = c / r

Then, we know that: ω = 2πν
is the frequency of rotation of bubbles)

So we obtainω = c / r = 2πν

Then: 2π r = c / ν = λCbubble

λCbubble from is the compton wavelenght of rotating bubbles

We know that radius r of bubbles is equal to the Compton wavelength of the neutron:

λCneutron = 1,3205 fm

We obtain: 2π λCneutron = λCbulle

If the Compton wavelength of rotating bubbles of neutron is 2π times more high that Compton wavelength of the neutron, we can deduce that its mass (Mbn) is 2π times more low.

Mbn = Mn/2π

The same calculus allows to obtaining the mass of the bubbles of proton (Mbp):

Mbp = Mp/2π

 Copyright : Benoît PRIEUR; Contact: bubblestheory at gmail.com